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Application Note: You CAN be too RichBy Klaus
Allmendinger, VP of Engineering, Innovate Motorsports
Many people with turbochargers believe that they need to run at
very rich mixtures. The theory is that the excess fuel cools the
intake charge and therefore reduces the probability of knock. It
does work in reducing knock, but not because of charge cooling. The
following little article shows why.
First let’s look at the science. Specific heat is the amount of
energy required to raise 1 kg of material by one degree K (Kelvin,
same as Celsius but with 0 point at absolute zero). Different
materials have different specific heats. The energy is measured in
kJ or kilojoules:
Air ~ 1 kJ/( kg * deg K) Gasoline 2.02 kJ/( kg * deg
K) Water 4.18 kJ/( kg * deg K) Ethanol 2.43 kJ/( kg * deg
K) Methanol 2.51 kJ/( kg * deg K)
Fuel and other liquids also have what's called latent heat. This
is the heat energy required to vaporize 1 kg of the liquid. The fuel
in an internal combustion engine has to be vaporized and mixed
thoroughly with the incoming air to produce power. Liquid gasoline
does not burn. The energy to vaporize the fuel comes partially from
the incoming air, cooling it. The latent heat energy required is
actually much larger than the specific heat. That the energy comes
from the incoming air can be easily seen on older carbureted cars,
where frost can actually form on the intake manifold from the
cooling of the charge.
The latent heat values of different liquids are shown here:
Gasoline 350 kJ/kg Water 2256 kJ/kg Ethanol 904
kJ/kg Methanol 1109 kJ/kg
Most engines produce maximum power (with optimized ignition
timing) at an air-fuel-ratio between 12 and 13. Let's assume the
optimum is in the middle at 12.5. This means that for every kg of
air, 0.08 kg of fuel is mixed in and vaporized. The vaporization of
the fuel extracts 28 kJ of energy from the air charge. If the
mixture has an air-fuel-ratio of 11 instead, the vaporization
extracts 31.8 kJ instead. A difference of 3.8 kJ. Because air has a
specific heat of about 1 kJ/kg*deg K, the air charge is only 3.8 C
(or K) degrees cooler for the rich mixture compared to the optimum
power mixture. This small difference has very little effect on knock
or power output.
If instead of the richer mixture about 10% (by mass) of water
would be injected in the intake charge (0.008 kg Water/kg air), the
high latent heat of the water would cool the charge by 18 degrees,
about 4 times the cooling effect of the richer mixture. The added
fuel for the rich mixture can't burn because there is just not
enough oxygen available. So it does not matter if fuel or water is
added.
So where does the knock suppression of richer mixtures come
from?
If the mixture gets ignited by the spark, a flame front spreads
out from the spark plug. This burning mixture increases the pressure
and temperature in the cylinder. At some time in the process the
pressures and temperatures peak. The speed of the flame front is
dependent on mixture density and AFR. A richer or leaner AFR than
about 12-13 AFR burns slower. A denser mixture burns faster.
So with a turbo under boost the mixture density raises and
results in a faster burning mixture. The closer the peak pressure is
to TDC, the higher that peak pressure is, resulting in a high knock
probability. Also there is less leverage on the crankshaft for the
pressure to produce torque, and, therefore, less power.
Richening up the mixture results in a slower burn, moving the
pressure peak later where there is more leverage, hence more torque.
Also the pressure peak is lower at a later crank angle and the knock
probability is reduced. The same effect can be achieved with an
optimum power mixture and more ignition retard.
Optimum mix with “later” ignition can produce more power because
more energy is released from the combustion of gasoline. Here’s why:
When hydrocarbons like gasoline combust, the burn process actually
happens in multiple stages. First the gasoline molecules are broken
up into hydrogen and carbon. The hydrogen combines with oxygen from
the air to form H2O (water) and the carbon molecules form CO. This
process happens very fast at the front edge of the flame front. The
second stage converts CO to CO2. This process is relatively slow and
requires water molecules (from the first stage) for completion. If
there is no more oxygen available (most of it consumed in the first
stage), the second stage can't happen. But about 2/3 of the energy
released from the burning of the carbon is released in the second
stage. Therefore a richer mixture releases less energy, lowering
peak pressures and temperatures, and produces less power. A
secondary side effect is of course also a lowering of knock
probability. It's like closing the throttle a little. A typical
engine does not knock when running on part throttle because less
energy and therefore lower pressures and temperatures are in the
cylinder.
This is why running overly-rich mixtures can not only increase
fuel consumption, but also cost power.
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